Solving Pi Pi has been considered to be a transcendental number, but actually what we find is it is only transcendental from the perspective of anything other than base infinity. Once we move to base infinity, we can understand that the reason pi appears to be so transcendental is really due to a fact of the base 10 system interfering with the concept of number at base infinity or numbers have their own individual symbol. Whereas in base 10, we need to limit that creating a number grid which then interferes with our calculations. Through the examination of the infinite we are able to understand that the following equation will equal pi. Two e divided by one minus four pi equals 25 and a third that is the first pi equation the second pie equation is the square root of three divided by two pi divided by E equals one. Together these equations allow us to decode the number pi and we can understand that the functioning of number space works within the infinite. To begin with, we should understand that the number e is actually a composite of the reciprocal values of all factorial numbers. The Infinity of factorials therefore, combines all of the numbers within LF naught point five when we decide to rotate the number line into a 90 degree access into a 90 degree axis. Then, we are rotating the number line which will remain at a distance of infinity. This rotation comes about through a process we call zero squared in fourth dimensional mathematics. Once the line begins to rotate, it has moved to dimension from the first dimension of the line into the second dimension of the plane. And as it rotates into a 90 degree orientation, it will remain consistent with its density at the edge of the number line of infinity, we see the quarter pie being created. Therefore, to explain the equation more clearly, we are taking the number line and doubling it ie to a and then we are going to divide it by one minus four pi which is the difference between squaring one and the rotation of one around the axis of zero. In this instance, when we when we two and number one, we are talking about the infinite state of the numbers one, two and four. This is because we are working with infinities. And numbers at the end of infinity are represented by a minus one. In a sense, we can apply the number 1.999 to infinity times E divided by 0.999 to infinity minus pi divided by 3.99999 to infinity. It is this interaction of the three types of 999 to infinity that creates a small offset in the equation as we will see when we work out for the infinite part of the equation. From the two finite parts. We are able then to stand the infinite at the end of pi through the recognition of the number 25 plus one over three. The number 25 itself when extracted to a power of 100 becomes a quarter and here we can see that the quarter is represented underneath the number pi the fractional point one over three then becomes the additional fraction that is needed in order to expand infinity for that quarter. We can understand this in fourth dimensional mathematics. When we look at the completed circle which will equal a four pi this will be recognised within the equation for root three divided by two pi over E equals one or more precisely infinity minus one. When we look at the number cross the of the zero square we can see that when zero is squared, it is squared by the function of minus zero times plus zero, which equals negative zero in the southern polar position. This is what initiates the transformation of pi into the four other quarters therefore that is why we only need to calculate a quarter pie. Secondly, that the number he then is in a reciprocal space, which is between zero and one which contains all infinities is in fact being rotated within the zero space. And within that zero space, we find that the two nines are created which creates the number two a doubling function. When we see the other half of the three parts of the circle, we recognise that the density factor of infinity is one in comparison. Therefore we have a density factor of two in one of the quadrants of the circle and identity factor of one in the other. For this reason we are able to work out why the one over three, which is the one which has the double density part of infinity and three representing the half in half density when we look at it from the perspective of the infinite we can also find that from the number 25 It is a relatively simple process to manufacture the golden ratio. Additionally, we can also just we can also find the square root and divide by two, two. In fact, we can find the equation that will turn that will that will generate the number three which I think is to E the square root of two e divided by one minus four divided by pi which is our equation for the pie. We minus the 1/3 we plus one and we divide by two if we add one to the 25 we are actually creating the number 26 which becomes the prime number 13 times two, which is constructed from the numbers one and three. Just as the equal one over three is constructed by the same numbers if we wish to make the golden ratio we take the pie equation, we minus one over three to create 1/3 to create 25 We find the cubic root or the quad root of that number to find the square root of what 1.25 upon which we can add or minus a half to create the golden ratio. the second equation that is to do with the square root of three is primarily to do with the concept of that we are actually breaking infinity in half and E in the equation of the square of three three divided by two pi over equals one and we are looking at the midpoint of infinity at that point where the two E’s meet. We represent this as two triangles sat over each other which have a dimension of one in the horizontal and root three in the vertical. We all then taking the circle as root three and dividing it thus making it to the number one and therefore reducing the number e into its singular format. The division of a triangle into now that we have covered some of those details, just a few little things we would like to point out that actually if you take the number 25 plus one over three and times it by two, he will have your create the number 137 point 726 Which is pretty close to what we would call the fine structure constant which actually is found as a constant that structures the Space of the Universe. Whether this is of importance, but the number 137 is increasingly important. In the concepts of quantum physics.
In the next section, we will now discuss how we can solve for the infinite at the end of the number and show how the number pi is actually related to that the the equations that we’ve given. In a sense, what we can say is infinity minus one is what we’re looking at for the first part of the equation one which equals naught point 99999. So we know that that’s infinity minus one. However, we don’t know what the last number of he is. And we don’t know what the last number of pi is. However, because we know that the last number of the number nought point 999 to infinity is an odd number. Therefore, we can be assured that we must divide that number by another number in order to work out what is happening at the end of the number line to cause the disruption in the calculation. When we take the number 999 We fail therefore are limited to a very few options. Option number one would be to divide nine by two. Option number two would be to divide nine by four. And option number three would be divide nine by eight. This would create three options, or 4.5 foot nine over two, a 2.25 for nine over four and a 1.125 for nine over eight.
Next what we can do is we can compare the difference between 1.125 times 1.11 1.1 point sorry, next we can compare the difference between 1.1 to five times 4.5 equals 5.6 to five we can take the number nine and divide it by 5.625. We get the number 1.6. When we divide 1.6 by the number nine we minus if we take 1.6 divided by nine then we get the number 0.1 And then an infinite series of the number seven. Looking at the number seven when it divides into itself, we find that it will create a six digit number code 128557 1.285714
If we consider none of these numbers contained in number three, six or nine, and therefore we end up in a kind of infinite loop if we were to take that option. For example. We can take the number seven over nine which would take us back into the loop of the same code the same six digit numbers. We could take the number five, but then when we divided that over 16 we would get back to 1.125 which would be the same as dividing over nine over eight so we created a loop there. The number one wouldn’t work because you would end up a zero so that doesn’t work either. And the number and the other numbers. We can work out the structure. Eventually we end up going round in a infinite loop. And therefore we can exclude those pairings as the last numbers. This leaves us with a secondary option, which is to look at the difference between nine two and nine divided by four. The difference between 4.5 and 2.25 is exactly two 4.45 divided by 2.5 is two and then we have 2.25 divided by 1.25 1.125 is also two and that leads us to the number if we look at it two times two four. So that’s the mathematical structure of nine divided by two four and eight. What we find is that actually, the number four will lead us back around in a circle. And the number two will also lead us back round in a circle, which means none of those options can be applicable to the solution to the pie equation. However, because we have a function here on squaring it means we can also adapt a function of square rooting and find the midpoint of the infinite calculation. Therefore we must do is we must take number nine and we must divide it by the square root of two or more precisely in the infinite. We take the square root of two and times it by nine. And what we get is the number the square root of 162. We take the number 999 and we divide it by the number 162 And we get 6.166666 to infinity.
If we take the numbers 6.1666 To infinity and divide it by 1/3 we get the solution 2.55555 to infinity. This is the midpoint of the Infinity equation. We can understand that this is the midpoint by taking the number 2.055555 which is the result of the equation and dividing it by the number 37 which is a function of the triple digit code. And at that point we realise the result is 0.055555 5 million to infinity. The 5555 500 into infinity represents the midpoint split of the infinite of nine and we have there a number two at the start before the equation which then is reduced by two minus two once we apply the number 37 Therefore we have hit the midpoint and we have understood that the square root of two is the collapsing function that allows for the disk that creates the distortion shall we say in the calculations that we have suggested are the actual solutions to pi a base infinity we can look into these numbers in more detail if you wish. And when we do you can find we can analyse the number and because of the seven digit code let me just explain. When we when we work with a number seven it produces this seven digit code. Therefore everything must work in six digit number systems. In order for us to calculate at the end of infinity. And those six digit number systems break down into 999333 etc etc. And what we find is the number 37 is a way of collapsing those triple digit numbers into a single digit number ie reversing the infinite process. You can look into the number 37 in more detail. But if you take the square root of three divided by four for our pipe an end and divide that all by a what we find is that we get the number nought point 500 And then a triple 444. So the triple four voice is a signature of the infinite. Having said all of that, once we’ve got through the PI equation, what we can see is that on the other side when we take the square three divided by four pi and we then divide by e to equal one, we see that the number one is actually accompanied by a 000 then an 889 and that is also significant because the other numbers after that are 244. And when we see double numbers within the infinite we know there is a disruption caused and in this particular case is the number eight and the number four and we have ideas about what that means within the infinite structure of number space.
We will make another post shortly about the end of infinity and how we do these calculations and how we know these calculations work for the end of infinity working in sets of six numbers based on 999999. And in that way we can we can go into more detail about how we’ve solved pi throughout the new mathematics of fourth dimension, which will allow us then to have a much clearer idea also about some of the structures of the periodic table as well amazingly. So stay tuned and more to come from into infinity. Thank you very much.