The point solution okay answers to some questions coming in about the number e and the pie solution. So, obviously, he is also considered to be transcendental number. And in a sense we can understand why people think that to be the case. Yeah, from the perspective of one dimensional mathematics that is true. But when we go into the infinite suddenly all of that gets dispelled. So firstly, what we should do is we should just clarify about the F naught point five for those people who don’t know the solution. to L f naught point five and f naught point five is a density of infinity, which we find in reciprocal space. So you can imagine if, if we have reciprocal space, we can take it and we can divide the reciprocal space into two and then we can count one, two. So, let’s take a line. Yep. Well hold up a line in space, and it’s just held up by two points. Let me call that line one. Great. So actually bits from the distance of zero and one Yeah, but the line itself like on a guitar string, we say that’s the root note if you like, if I divide that note in half, if you’d like, yeah, we’ve got the number two now. But actually, if you think about it, I had 123 things now that are holding up a space of two. That’s actually what’s happening. I’ve got the the end of the the ends of the string. And another thing in the thing dividing it. It’s like, like a fence post. If you want to put up a fence. Yep, you need to have a post. Then you can have a fence panel, a post a fence panel, and then another post, and then your panel will stay up, won’t it? Yep. So that’s what we’re looking at here. When we look at this number space, this reciprocal numbers between zero and one, and what we’re doing is we’re dividing. So when it comes to the first the second division, all that’s done is that means if you look down the line if you would follow all those lumbers down the line like the number four would find a division with number two any any even number will find a division with the number two. So actually that will be excluded from the primes. So that we know that actually, we can now look at that centre point as a prime point for all all possible or even primes. So that’s what that number two is yes. Oh, there it is. It’s got rid of all those. Yep. And the next point, what happens is we move down and we divide the number line into three. Yep. And so as we’ve divided the number line into three, now we can see there’s a space where we’re where it was, where was number one Number one, now it’s because in the previous step was a dot wasn’t it yet, and now the.is divided and is divided by a space of one.
That’s right as that centre section in the midsection of the three. And so you could say that could form a sort of triangle, if you like. Yep. And it does you know that triangle is there. We draw a Vesica Pisces, we call it the Vesica Pisces inside of that line, and we can put a triangle above a triangle below. And because we know a triangle from the number one can contain all of the numbers. Yep, down to zero. Imagine we’ve got this triangle. It’s got a it’s got a line length, and as we’re getting smaller and smaller and smaller, so it’s diminishing towards zero. And so that space in the centre there that we’re looking at, will diminish as we as we start to divide the line more, won’t it Yeah. So that means that basically, we’ve just taken out all the primes of the number three, yeah, because we’ve just gone that. And so as we as we diminish that line, you can see something in our literature called the prime number curvature. That’s what we’re looking at here. Yeah, is that the primes are actually ones that carry unique centre space. That’s what it is the centre space in this in this division of three. So so we know that there were there were going to be within that triangle. And what you notice is one triangle goes up, there’s one triangle that goes down. And so every, every space in a sense as it goes down, I’m gonna have a reflection going up. Yeah. And this is how we kind of view the number line in a way right? We can view it like this. So what’s happening is in a solution to L f naught point the LF naught point five is what we’re doing is we’re taking we’re taking the one yeah, we’re saying that’s one. So that’s like a one there. And it’s between those that those two posts and then when we divide into two we say there’s a half, that’s the first half, and then there’s the second half. And so we add the first half, which is a half plus the second half, which is two over two, which equals one, and then they equals 1.5. So you can see we’ve progressed here at half rate. Yeah, we’ve gone from one to 1.5. Whereas on the other side, we’re going from one to two, yep. And as we go to then two, three to four to five to six, and seven. So on the other side, we’re actually only going to progress in half steps and that means that we have an infinite density of naught point five for that in the whole whole number fractions within reciprocal space. Okay, so now that we understood reciprocal space in a little bit more detail, let’s have a look at the numbers now to understand how this can be so that we can sort of work it out a little bit more detail. So when we first started, actually, we’re starting with the number zero and you could say that basically what we needed to do is stretch that line into one. We’re not going to get into that how we did that. Exactly. Ryan stop. Yep. But what it does is you could say, let’s say the line with one it could be your starting point for this exercise, so we’re going to put that as he in zero which is zero, yep. And then what we can do is every step that we move down a little and say we’re gonna make a step and divide into to make a step divide into three. We’re gonna break those ordinal ordinal numbers in the downwards direction, like that. Yep. So that’s how that works. Yeah. Now if I go from f of zero, we’ve also got another ordinal number, which is me counting one across, you see, I’m actually counting across as we move down in an ordinal of One Direction. There’s another ordinal. Now that goes one, two, and counts across as a moving ordinal to the second ordinal. It counts across 123. We have an offset of the ordinals of two ordinal numbers. Yeah. And so what we’re doing is we’re able to count down and we’re able to count across at the same time. This is called simultaneous calculation. So simultaneous calculation is just a fancy word for we can perform a calculation and bear that in mind what’s happening in one space. As we look at another space and see what’s happening with the numbers in one in another direction. And what happens is, is that we look then, is that we’re actually building numbers. In space, we can put this into a triangle. And what we see is, let’s say we make this now into a triangle, and we start with a circle. Which is one, we start with two circles below that one to using it, and the next couple of that 123. So you can see we’re building up a set of triangular numbers, and we have evidence to show that out works in your triangle numbers. And so what happens then, well, if you think about it, if I’m going down on these ordinal numbers 123 And so it turns out that which will be a certain difference of infinity. What we’re really doing is then with a number he is with these all reciprocal values, so we’re actually adding reciprocal Zanmi we’re adding, we’re adding the one to a half Yeah, one and two, and this rule reciprocal factorial so Okay, good. One plus two, then we’re taking one plus two plus three equals two. And we’re joining all that they’re called factorials, aren’t they? Yeah. And a number is a combination of all these factorials so we can see what’s happening. Now let me just explain something then by unwrapping the number a little bit we can do that by using zero squared. And what we find is, is that we can place now an orientation for the numbers we got the ordinal numbers running in one direction, okay, and we got the another set of ordinals running in the 90 degree axis. So to those things, yeah. And when we make the triangle what we see is down one side of the triangle, we’ll get the numbers growing 1234567 all the way to infinity. And on the other side of the numbers, what we’ll see is just the number 1111111, all the way to infinity. So, and what we’ll find is then the variation between all of those numbers in between. So that’s the number three really, it’s just compiling all these numbers into one nice, infinite infinite density. So now that we’ve got that understanding of what EA is, we can move over now and place the ordinals in the right orientation. The Cardinals are going between the two ordinals Yep. Are going at a you could say one axis. Yeah. So we could write the axis of the Cardinals on one axis there the 45 degree. And what we’ll do is we’ll offset the ones behind the second ordinal. Yeah, the the infinity of ones behind the second ordinal. And the reason we do that, you could say it’s like the minus one of the ordinal or the plus one of the ordinal. That brings it back into alignment with the other ordinal set. So we’re going to place that behind now in and what we get is then we get a right angle degree of a two with a one heading on the in the parallel heading, say in this direction. Right? Yep. And we’ve got the O two heading in the down direction. And we’re going to have our triangle number c, which we’re going to call for our Cardinals heading a 45 degree, and then we’re going to have a plus one running 45 degrees behind the O twos, the ordinal twos. So now that we’ve got that, we can see that if we rotated that through pi, ie if we rotated the number through the PI function, which is what we do with the with the what we see is actually the ordinals now will shift and ordinal number one will point up an ordinal number two will take the position of ordinal number one, and the Cardinals will move into a new space and the plus one will take the position of the Cardinals. So what’s happening is as we’re rotating that line, through one circuit, we’re doubling it, you can say we’re doubling the function and through a rotational function, which is the PI the quarter pi function, and then the number plus one is now occupying the Cardinals. So or you know, which becomes in a way the thing that holds the content, you know, the continuation, the Cardinals, wherever you choose a cardinal there’s always an angle plus one. That’s the nature of infinity. Yeah, that’s why the more you walk towards infinity, the further away you get from it, which is one of our things. Yeah. So let’s just carry on then. And just think about the other solution, which was the root three root three solution, where we actually managed to rotate the whole circle you got we can get rid of the four pi, and instead of that root solution, we can just get down to just one pie. Yeah. Which means a full rotation, isn’t it? Yeah. Of the of the of the circle, and that’s exactly what we need. Let me just check the equation here. Yeah, we have it. The square root of three divided by two pi over E now is two pi because obviously, what we’re looking at here is metaphysical pi, isn’t it? Yeah. Because everything’s happening on a quarter of a circle, which means that the diameter is not one. It’s the radius. That’s one, and that’s why we have two pi. So that’s that equation. Now we can see which is a force for rotation. Once we’ve gone through the full rotation, we can make a map now of the number e moving through its full rotation, and what we find is that the ordinals will take the xy position and they will swap places being ordinal one ordinal two, they will swap Yeah. So they could either be depending on the orientation at that time, time space, one or two and the Cardinals and the nine minus n plus one, which can become minus one to hold the car to hold the Cardinals process and define the number for the cardinal that will be happening on the 45 degree axis. So we’ve got a nice eight sided shape there. And what we find is that the ordinals themselves have a particular type of infinity. So now that we’ve got the Infinity map of the rotation of the cardinal ordinal space, when the number three in this, which which is the solution to pie. If you think about it, you know, because we’ve gone through four rotations. Yeah, good check. So then what we need to do is we just count through, and what we find is that now we’re going to go back now to our division of the line. Yep. And when we got to the third, we’ve got the triangle Yeah. Which is a root three solution. Yeah. And so you can see now that the root three solution is is that triangle, and that we divide in two because the root three is actually divided by two itself. So there you go, in the Vesica Pisces which came in the third division, which then took out you know, all of the three primes. Yeah, so we’ve taken out the two primes, we take the three primes, the third division, yeah. And then that triangle forms and inside that triangle, we will find all of the other prime numbers and all of the other stuff that we want to find in number space. And because it’s it contained within that triangle, which is the number three, which is that there’s one triangle going up there’s one triangle going down, one for the ordinal numbers, you could say it can work like that, if you if you think about it, we have an up triangle and a down triangle, right? And so we can put the number one, one set of infinity there, one seven, infinity below for an upper triangle on a downward triangle. Okay, so now let’s count up the ordinal numbers and see where we are. If you imagine when we get to this three stage, what we’re really happening is we’ve gone zero, haven’t yet one to two, the second step if you like, yep. 012 is a number two, it means we have to minus the zero set, we have to minus the one set, but we can keep the two set because we’re still there. So basically, that’s infinity minus two. Yep. On the other side, what you could say is here we have the infinity minus four. Why? Because basically, as we moved across, we’ve counted a step 12341234 You can see the divisions 1234 There’s one at the end there and one of the end there, then it becomes three then because 1234 By the time we get those divisions, those cardinals are now forced to finish the minus four we say Yeah, right. Yeah. So looking finish the minus to infinity minus four, square root of three in the middle. Yep. So that’s the triangle in the middle there. And let’s put a circle around that and call it an infinite type of infinite Yep, of pi, the type of pi pi infinity, isn’t it? Yeah. And what we can do, then that will be pi to the square root of three reduction. And what we can do then is we can take the infinity, we can divide it into two. And what we have then is that this if you imagine if we minus the widow of the other oh, we’re going to be left with infinity minus two. And that can be separated into one triangle separate into the other triangle. And that means that we can have LF nought point five as infinity density, and that explains why we have this two three ratio. You can also find out more about the two three ratio and how it goes on to create the square root of two, which is why music spirals down in octaves through the square root of two very important knowledge. And once we understand all of that, we can understand that the number is actually encapsulating the whole number space. And as it rotates that through the pie function is maintaining the infinite density ratio of one to one through the squaring function. Okay, and it’s because it’s contained within a triangle. For those people who want to get to more advanced lessons on number three, we can start to look at the three dimensional number space, which is not based on the square tapestry. It’s based on the hexagon. Yes, that’s right, the hexagonal tapestry, but we won’t go into that just yet. Because that takes us into 03. And we’re not quite ready even with zero squared yet. So. So anyway, just that’s a little bit of knowledge about the number ie how it works with two sets of ordinals. Yeah, which are offset by one. Now remember, our ordinals already offset by ones that makes it a one to offset. Yep. And then as we go and count through, what we’re doing is actually we find that actually, the numbers here are actually counting across on the 1234 with the dots that are dividing the three, you said to mean, so what’s happened is those twos have collapsed into 121231234. You can see what I’m saying the dots themselves. There’s another type of secondaries. That’s the other number we’re not looking at. Yeah. And it’s those fence posts that hold up the number space that we’re interested in. When we talk about the ordinals and the ordinals move down in in a sequence as well when we divide the line into more and more more pieces, which in the sense will just be further division of the central triangle into smaller and smaller parts. So we don’t need to keep dividing lines, we can just look at the centre from now on, can’t we? And that means we can discard the two thirds of that number space, and we could focus just on the number space that we actually need. So that’s going to be a lot of things for some mathematicians to think about. And we hope that’s clarified some of the information about the number e and its function with the relationship to the pie and the pie equation. Thank you very much for listening. My name has been calling power. This has been a broadcast from into infinity providing the pie solution in fourth dimensional mathematics.